Question

i) ( x^{2}-x-2=(x+1)(x-2) )
for ( x rightarrow 2^{-} quadleft|x^{2}-x-2right|=|(x+1)(x-2)|=-(x+1)(x-2) )
( irangle )
( [x] ) when ( 2

# Single Choice +4/-1 a/x*=30=31 «<2 2+1-Y b Y=2 =2 * -IN] «>2 X> 2 X-2 (I) denotes greatest integer function). If $(x) is continuous at x = 2 then: A a =1, b = 2 B d=1, b=1 C a =0,b=1 D a= 2,=1

Solution