Question

( x=1 cdot 2 x cdot 0^{14} e^{-2 frac{5000}{1}} cdot sec ^{-1} )
Taking Log" both sides
( operatorname{cog} 10=log 1 cdot 2 times 10^{19}+(-25000) ! frac{1}{7} sec ^{2} )
( log k quad ) ve log the will give a hypersolic curre.
( log quad k-quad vee beta quad frac{1}{pi} )
will give a
straight line
OPtion D i g wrreat

# Single Choice A reaction rate constant is given by : 0.0 121014eI sec. It means : k =1 log k verses log T will give a straight line with a slope as 25000 log k verses log T will give a straight line with a slope as - 25000 log k verses T with give a straight line with a slope as - 25000 log k verses 1/T will give a straight line

Solution