Question

( lim _{x rightarrow 0^{+}} x([x]+|x|) sin [x] )
( lim _{x rightarrow 0^{-}} frac{-x([x]+|x|) sin (x)}{x} )
( lim _{x rightarrow 0^{-}}-1(1+0) sin (-1) )
( =frac{x+0}{=} sin frac{1}{=} )
( pi )

# Single Cruce lim [x]-/ */) sin(x] A sin 1 B -sin1

Solution