Question

( begin{aligned} tan (45+x) &=frac{tan 45+tan x}{1-tan 45 cdot tan x}=frac{1+tan x}{1-tan x} therefore tan (45-x)=& frac{1-tan x}{1+tan x} frac{tan (45+x)}{tan (45-x)}=frac{frac{1+tan x}{1-tan x}}{frac{1+tan x}{1+tan x}} &=frac{(1+tan x)^{2}}{(1-tan x)^{2}} therefore x=2 & frac{1}{2} end{aligned} )

# sittana tan (45+2) tam 1950_2) Itana, front go I tam 60°

Solution