Question

( 5 x-1<(x+1)^{2} )
( x^{2}+2 x+1>5 x-1 )
( x^{2}-3 x+2>0 )
( (x-1)(x+2)>0 )
( quad frac{x in(-infty, 1)(2 infty)}{7 x+3} )
( (x+1)^{2}<7 x+3 )
( x^{2}+2 x+1<7 x-3 )
( x^{2}-5 x+4<0 )
( (x-1)(x-41<0 )
( frac{x}{6} x(1,4) )
( therefore x in(2,4)] )

# Solve in the set of integers 5x-1< (x+1); <7x-3.

Solution