Question

Solve in the set of integers 5x-1< (x+1); <7x-3.

JEE/Engineering Exams

Maths

Solution

4.0 (1 ratings)

( 5 x-1<(x+1)^{2} ) ( x^{2}+2 x+1>5 x-1 ) ( x^{2}-3 x+2>0 ) ( (x-1)(x+2)>0 ) ( quad frac{x in(-infty, 1)(2 infty)}{7 x+3} ) ( (x+1)^{2}<7 x+3 ) ( x^{2}+2 x+1<7 x-3 ) ( x^{2}-5 x+4<0 ) ( (x-1)(x-41<0 ) ( frac{x}{6} x(1,4) ) ( therefore x in(2,4)] )