Question

[
tan (A+B)=frac{tan A+tan 15}{1-tan A tan B}
]
( tan (A+B)=frac{-frac{1}{2}+frac{1}{3}}{1+frac{1}{6}}=frac{-I}{6} times frac{6}{5} )
( tan left(begin{array}{c}A+B)=-frac{1}{5} C A+B D=tan ^{-1}left(-frac{1}{5}right)end{array}right. )

# soon) tan A = 1 ton BE a las n A+B=2 (B) 30ces sñ sets None

Solution