Question

2
comefider the reacrion
Both Br and el react in 1: 1
moles of Rral formed =
[
0 cdot 0.250 text { mole } d_{2} x
]
( frac{2 m a cdot b r c d}{1 m o 1 c d_{2}} )
( 0.0500 mathrm{mol} e )
( 5 cdot 7<82(text { theoritical }) )
-1. Yield is 80 the
[
begin{array}{l}
frac{x}{5 cdot 768} times 100=80+
x=4 cdot 6144906013
end{array}
]
(a) mass of Bral formeal ig ( [4 cdot 6144910 )
Amount of ( B r_{2} ) leforig ( div 0.005 ) moles wel gho ( n-13 mathrm{f}_{2} mathrm{leb}+18=[0.7 mathrm{g} )
( 0 cdot 49 )

# su reagent (in moles) D-2. The percent yield for the following reaction carried out in carbon tetrachloride (CC14) solution is 80% Bra+Cl 2BICI (a) What amount of BrCI would be formed from the reaction of 0.025 mol Bra and 0.025 mol Cl? (b) What amoumt of Brz is left unchanged?

Solution