su reagent (in moles) D-2. The perc...
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su reagent (in moles) D-2. The percent yield for the following reaction carried out in carbon tetrachloride (CC14) solution is 80% Bra+Cl 2BICI (a) What amount of BrCI would be formed from the reaction of 0.025 mol Bra and 0.025 mol Cl? (b) What amoumt of Brz is left unchanged?

JEE/Engineering Exams
Chemistry
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2 comefider the reacrion Both Br and el react in 1: 1 moles of Rral formed = [ 0 cdot 0.250 text { mole } d_{2} x ] ( frac{2 m a cdot b r c d}{1 m o 1 c d_{2}} ) ( 0.0500 mathrm{mol} e ) ( 5 cdot 7<82(text { theoritical }) ) -1. Yield is 80 the [ begin{array}{l} frac{x}{5 cdot 768} times 100=80+ x=4 cdot 6144906013 end{array} ] (a) mass of Bral formeal ig ( [4 cdot 6144910 ) Amount of ( B r_{2} ) leforig ( div 0.005 ) moles wel gho ( n-13 mathrm{f}_{2} mathrm{leb}+18=[0.7 mathrm{g} ) ( 0 cdot 49 )
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