Question

tann + sea Perove that d o

Defence Exams

Maths

Solution

4.0 (1 ratings)

( y=tan x+sec x ) ( y=frac{sin x+1}{cos x} ) ( frac{operatorname{dy}}{d x}=frac{cos x(cos x)+sin x(sin x+1)}{cos ^{2} x}=frac{1+sin x}{1-sin ^{2} x}left[cos ^{2} x=1right] ) ( frac{d y}{d x}=frac{1+sin x}{cos ^{2} x}=frac{sin x}{cos x}=frac{1}{(1-sin x)} ) ( frac{d y}{d x}=frac{1+sin x}{(1+sin x)(1-sin x)}=frac{cos x}{(1-sin x)^{2}} ) ( frac{d^{2} y}{d x^{2}}=frac{0-(0-cos x)}{(1-sin x)^{2}}=frac{1}{2 x} )