Target : JEE (Main + Advanced) 2021...
Question

# Target : JEE (Main + Advanced) 2021/19-05-2019/Paper-2 a re-cong-aban en bro then value of a + b + c is then value of a + b + c is

JEE/Engineering Exams
Maths
Solution
99
4.0 (1 ratings)
( b c+frac{1}{a}=c a+frac{2}{b} quad a=a b+frac{7}{c}=frac{1}{a+b+c} ) ( Rightarrow frac{a b c+1}{a}=frac{a b c+2}{b}=frac{a b c+7}{c}=frac{1}{a+b c} ) Using the ploperty ( frac{b_{1}}{a_{1}}=frac{b_{2}}{a_{2}}=frac{b_{3}}{a_{3}}=frac{b_{1}+b_{2}+b_{3}}{a_{1}+a_{2}+a_{3}} ) We have ( frac{a b c+1}{a}=frac{a b c+2}{b}=frac{a b_{b}+7}{c}=frac{3 a b c+10}{a+b+c}=frac{1}{a b+c} ) ( cos ^{2} a b c=-3 ) ( Rightarrow quad-frac{4}{a}=frac{-1}{b} quad b=frac{(a)}{c} 4=frac{1}{a+b+c} ) ( Rightarrow a=-4(a+b+c) ) ( b=-frac{2}{4}(a+b+c) ) ( c=104(a+b+c) ) ( Rightarrow quad a b c=frac{-2 x-1 times 4}{(2 a+c+2+10}(a+b+c)^{3} ) ( beta ) ( (a+b+c)^{3}=frac{3}{8} ) ( Rightarrow ) ( log _{a rightarrow infty}(1) sqrt{b} quad a+b+c=frac{sqrt[3]{3}}{2} ) Therefou concet ans is ( (d) )