Te JOV 31. A body is projected from the ground with a velocity v = (3i+10j)m s-1. The maximum height attained and the range of the body respectively are (a) 5 m and 6 m (b) 3 m and 10 m (c) 6 m and 5 m (d) 3 m and 5 m . :: A

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( v=(3 hat{i}+10 hat{j}) m / s ) ( Rightarrow v_{x}=3 ) and ( v_{y}=10 ) ( therefore ) Maximum height attained ( H=frac{v_{y}^{2}}{2 g} ) ( =frac{10 times 10}{2 times 10}=5 m ) Range ( =v_{x} times T=v_{x} times frac{2 v_{y}}{g}=frac{3 times 2 times 10}{10}=6 mathrm{m} )

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