Question

( b )
( angle )
( x+y+620=180^{circ} quadleft{begin{array}{l}22left(begin{array}{c}angle a+L b) -ln +y=360^{circ}end{array}right. )
( =1180^{prime} )
( 80+62 )
( 2left([a+L b)=360-118^{2}right. )
( 2 times 242^{circ} )

# TEMATICS UCPD LUNDAMENTAL MANSI 12. In figure 6.130, the sides AB and AC of AABC are produced to points D and E If bisectors BP and CP of ZCBD and ZBCE respectively meet at point P, then find and E respectively P, then find ZBPC. LINES AND 20. In figure 62° 22. In figur FIGURE 6.130

Solution