Question

n is thom 2 to 10
: ( k ) will ( h ) LCM ob ( (2,3,4,5,6,7,8,9,10)-1 )
[
begin{array}{l}text { LCM of }(2-10) text { is } 2520 k=250 quad 2520-1=2519end{array}
]
Sum ob digits ( =2+5+1+9=17 )

# Tet Khe the smallest positive integer with the propertu that for all n such that 2 sn 10, when divided bu'n VEEAdor it leaves a remainder of n-1, then the sum of the digits of K equals. (A) 12 (B) 13 (C) 15 (D) 17 rode BOAG AH

Solution