Question

( 22 mathrm{m} ) of ( mathrm{co}_{2} )
( frac{22}{44} times 2 times N_{A}=n_{0} cdot 900 )
moles of 0 : ( Rightarrow frac{22}{44} x^{2}=1 ) mol
80 molus ( y(0=1 )
( I=frac{omega t}{28} )
( (x=28 g m) )
gis it Right??

# TexCalculate the weight of CO having the same number of oxygen atoms as are present in 22g of carbondioxide.

Solution