Question

( begin{aligned} & angle R=frac{pi}{2} Rightarrow & quad P+varnothing=frac{pi}{2} end{aligned} )
( 3 frac{P}{2}+frac{Q}{2}=frac{pi}{4} )
( Rightarrow tan left(frac{P}{2}+frac{Q}{varphi}right)=1 )
( Rightarrow quad+a nleft(frac{P}{2}right)+tan frac{varphi}{2}=1-tan frac{P}{2} cdot tan frac{varphi}{2} )
( sum frac{-b}{a}=1-frac{c}{9} )
( =5-b=a-c )
( Rightarrow quad a+b=c )

# Tf tan .8 Nola In a triangle PQR, ZR = ind tan are the roots of ax2 + bx + c = 0, a =0 then - (A) a = b + c (C) b = c [AIEEE-2005] (B) c = a + b (D) b = a + c

Solution