Question

( cos y^{2}=4 a(x-b) )
( 2 y y^{prime}=4 a )
( therefore a=frac{y y}{2} )
( 2left[y^{2}+y y^{prime prime}=0right. )
( 8 y^{prime 2}+y y^{prime prime}=0 )

# The differential equation of all Coaxial parabolas y - 4a (x-b), where a and bare arbitrary constants.is d'y dy (A) dx 130118116771 V dx

Solution