Question # The given diagram shows two infinite line of charges having equal (in magnitude) linear charge density but with opposite sign. The direction of electric field at any point on x-axis for ( (x>0) ) is given by the unit vect

# The given diagram shows two infinite line of charges having equal (in magnitude) linear charge density but with opposite sign. The direction of electric field at any point on x-axis for ( (x>0) ) is given by the unit vect

(A) ( cos theta hat{mathrm{i}}+sin theta hat{mathrm{j}} )

(B) ì

(C) j

(D) ( -sin theta hat{i}+sin theta hat{j} )

Solution

from the tignec component of electric field due to positive charge along ( x ) -anis in

[

=f cos (90-theta)=sin theta

]

component of elective field due to - re is along - ue x ans and is equal fo

chage

[

=E sin theta

]

So het electric field along Xaris in 0 component of electric field due to twe

( y ) an

[

=E cos theta

]

So net fiel is along the ( y ) anis the is ( (c) hat{jmath} )