Question

AP ginen in ( =50,48,46,44, ldots )
So, commonidyterence ( (d) dot{Delta}=-2 ) Art teum ( f a)=50 ) The sum will be maximum if last tenm is OC last non negative integect So, last trim ( left(a_{n}right)=0 )
( S_{0}, quad a_{n}=a+(n-1) d )
[
begin{array}{l}
0=50+(n-1)(-2)
0=50+(-2 n)+2
-50+2=(-2 n)
-52=-2 n
-52=n=26
-2
end{array}
]
of terms ( (n)=26 )
1.
[
=frac{26}{2}left[begin{array}{c}
50+0]=13 times 50
=650 text { Ang }
end{array}right.
]

# The maximum value of the sum of the A.P. 50, 48, 46, 44, .................... is - (A) 325 (B) 648 (C) 650 (D) 652

Solution