Question
The motion of a particle along a straight line is

The motion of a particle along a straight line is
A described by equation ( x=8+12 t-t^{3}, ) where ( x ) is in metre and ( t ) in second. The retardation of the particle when its velocity becomes zero is
Solution

( x=8+12 t-t^{3} )
( v=12-3 t^{2} )
( 0=12-3 t^{2} )
( t^{2}=3 t^{2} )
( t^{2}=4 )
( t=2 )
( a=-6 t )
( a=-6 times 2 )
( =-12 m / 3^{2} )