Question
[
begin{array}{l}
qquad begin{array}{c}
x^{2}=2 y
2 x=2 frac{d y}{d x} Rightarrow frac{d y}{d x}=x
end{array} & begin{array}{l}
left(x_{1}, frac{x_{1}^{2}}{2}right)
text { Let the pout al- curve }left(x^{2}=2 yright) text { be }left(left(x_{4}+8 xright)right)
end{array}
end{array}
]
( Rightarrow ) slope of temgent ( =x_{1} )
[
begin{array}{l}
m_{1} m_{2}=-1
3left(frac{3-frac{x_{1}^{2}}{2}}{0-x_{1}}right)left(x_{1}right)=-1
end{array}
]
( Rightarrow quad 6-x_{1}^{2}=lambda quad Rightarrow quad x_{1}^{2}=84 Rightarrow x_{1}=2 )
Powt ( =left(2, frac{2^{2}}{2}right)=(2,2) )
Ophion c

The point (0,3) is nearest to the curve x2 = 2y at (a) (222,0) (b)(0,0) ©)(2,2) (d) none of these
Solution
