Question

( 1^{x}+2^{x}+1 ) has a range (1000)( [text { put } x=-infty] )
( thereforeleft[4^{x}+2^{x}+1right] ) will be ( I^{+} )
ans) ( 4 I^{+} )

# The range of f(x) = (4x + 2x + 1]; (where :) denotes greatest integer function) is (1) 1* - {1, 2} (2) 1 (3) (4) /

Solution