The rate constant of a certain reac...
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The rate constant of a certain reaction is given by: log, ok = 5.4.212 Calculate the activation energy at 127°C.

11th - 12th Class
Chemistry
Solution
172
Rating
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From the formulae: ( mathrm{k}=mathrm{Ae}^{wedge}(-mathrm{Ea} / mathrm{RT}) ) ( log mathrm{k}=log mathrm{A}-2.303 mathrm{Ea} / mathrm{RT} ldots ldots ldots(1) ) Given eqn. is: ( log k=5.4-212 / T ldots ldots ldots ldots ldots ldots .(2) ) Compariing both the eqns. We get, ( 2.303 mathrm{Ea} / mathrm{R}=212 ) ( mathrm{Ea}=>212^{*} 25 /left(3^{*} 2.303right)=767.11 mathrm{J} )
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