The solution of the equation log, (...
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The solution of the equation log, (sin x + cos x) – log (cos x) + 1 = 0 is (BO (A) tan--- (D) None of these tan 1 whor of distinct solutions of

JEE/Engineering Exams
Maths
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is, ( log _{a} b=frac{log b}{11} ) of ( a ) lo, la" will be: ( log (sin x+cos x)-log cos x ) tog ( 2 a^{2} ) ( t mid=0 ) ( log (sin x+cos x)-log cos x= ) ( -log 2 ) ( log left(frac{sin x+cos x}{cos x}right)=0 ) ( log 1 / 2 ) ( tan x+1=1 / 2 ) ( tan x(z=-1) 2 ) ( x=tan ^{-1} 1 / 2 ) Option G
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