The value(s) of x for which the function T 1-x . x<1 f(x)= (1-x)(2-x), 12 fails to be continuous is(are) : Α 1 B 2 C 3 All real numbers

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( f(x)=|-x| quad x<1 ) ( frac{(1-x)(2-x)}{3-x} frac{1 leq x leq 2}{x>2} ) has chancosto fail It nets only at ( x=1,2 ) Lets cheas it ( a+x=1, quad f(1)=0 ) [ operatorname{lif}_{rightarrow 1} f(x)=0 ] ( therefore ) Continuous at ( x=1 ) ad ( n=2 ) [ fleft(x^{+}right)=1 ] ( f(2)=0 ) ( Rightarrow ) limit does not exist ( Rightarrow ) dis continousat ( n=2 ) Ans (B)

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