The vapour pressure of a saturated ...
Question

# The vapour pressure of a saturated solution of sparinglysoluble salt CKCL.) was 17.20 mm Hg at 27 C. If the vapour pressure of pure H.O is 17.25 mm Hg at 300 K, what is the solubility of sparingy soluble salt XCI, in molestre (B)200102 (A) 4.04 * 10% (C) 2.02 102 (D) 4.04 10%

JEE/Engineering Exams
Chemistry
Solution
217
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For saturated solution of sparingly soluble salt ( mathrm{XCl}_{3}(mathrm{i}=4) ) ( frac{Delta mathrm{P}}{mathrm{P}_{mathrm{A}}^{circ}}=mathrm{i} mathrm{X}_{mathrm{B}} Rightarrow frac{17.25-17.20}{17.25}=frac{0.05}{17.25} ) ( 2.9 times 10^{-3}=4 mathrm{X}_{mathrm{B}} ) ( mathrm{X}_{mathrm{B}}=7.246 times 10^{-4}=frac{text { Moles of } mathrm{XCl}_{3}}{text { Moles of } mathrm{XCl}_{3}+frac{1000}{18}} ) ( frac{10,000}{7.246}=1+frac{1000}{18 times text { Moles of } mathrm{XCl}_{3}} ) (Basis of calculation 1 litre saturated solution) ( 1380=1+frac{1000}{18 times text { Moles of } mathrm{XCl}_{3}} ) Moles of ( mathrm{XCl}_{3}=frac{1000}{18 times 1379}=4.028 times 10^{-2} ) [ begin{array}{c} mathrm{K}_{mathrm{sp}}=27 mathrm{S}^{4}=left(4.028 times 10^{-2}right)^{4} times 27 =263.24 times 27 times 10^{-8} =7.107 times 10^{3} times 10^{-8} =7.1 times 10^{-5} approx 7 times 10^{-5} mathrm{M}^{4} end{array} ]
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