Question # The velocity of a freely falling body changes as ( g^{p} h^{q} ) where ( g ) is acceleration due to gravity and ( h ) is the height. The values of ( p ) and ( q ) are

# The velocity of a freely falling body changes as ( g^{p} h^{q} ) where ( g ) is acceleration due to gravity and ( h ) is the height. The values of ( p ) and ( q ) are

(a) ( 1, frac{1}{2} )

(b) ( frac{1}{2}, frac{1}{2} )

(c) ( frac{1}{2}, 1 )

(d) 1,1

Solution

( v=u+a t )

( v=0+g t Rightarrow v=g t )

( v^{2}=u^{2}+2 a s=0^{2}+2 g h )

( v^{2}=2 g h )

( v times g^{1 / 2} cdot h^{1 / 2} )

p = ( =frac{1}{2}, q =frac{1}{2})

option (b)