The velocity of a freely falling bo...
Question
The velocity of a freely falling body changes as gphq where g is acceleration due to gravity and h is the height. The values of p and q are
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The velocity of a freely falling body changes as ( g^{p} h^{q} ) where ( g ) is acceleration due to gravity and ( h ) is the height. The values of ( p ) and ( q ) are
(a) ( 1, frac{1}{2} )
(b) ( frac{1}{2}, frac{1}{2} )
(c) ( frac{1}{2}, 1 )
(d) 1,1

JEE/Engineering Exams
Physics
Solution
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The velocity of a freely falling body changes as gphq where g is acceleration due to gravity and h is the height. The values of p and q are
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( v=u+a t )
( v=0+g t Rightarrow v=g t )
( v^{2}=u^{2}+2 a s=0^{2}+2 g h )
( v^{2}=2 g h )
( v times g^{1 / 2} cdot h^{1 / 2} )

p = ( =frac{1}{2}, q =frac{1}{2})
option (b)

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