Question
The work done on a particle of mass ( m ) by a force, ( Kleft[frac{x}{left(x^{2}+y^{2}right)^{3 / 2}} hat{mathbf{i}}+frac{y}{left(x^{2}+y^{2}right)^{3 / 2}} hat{mathbf{j}}right](K ) being a constant of appropriate dimensions), when the particle is taken from the point ( (a, 0) ) to the point ( (0, a) ) along a circular path of radius ( a ) about the origin in the ( x ) - ( y ) plane is
, when the particle is taken fr](https://images.instasolv.com/QuestionBank/5cf3a4ae8c62d929d0f5719b/crop_image.png)
The work done on a particle of mass ( m ) by a force, ( Kleft[frac{x}{left(x^{2}+y^{2}right)^{3 / 2}} hat{mathbf{i}}+frac{y}{left(x^{2}+y^{2}right)^{3 / 2}} hat{mathbf{j}}right](K ) being a constant of appropriate dimensions), when the particle is taken from the point ( (a, 0) ) to the point ( (0, a) ) along a circular path of radius ( a ) about the origin in the ( x ) - ( y ) plane is
(a) ( frac{2 K pi}{a} )
(b) ( frac{K pi}{a} )
(c) ( frac{K pi}{2 a} )
(d) 0
Solution
, when the particle is taken from the point (a,0) to the point (0,a) along a circular path of radius a about the origin in the x - y plane is](https://instasolv1.s3.ap-south-1.amazonaws.com/QuestionBank/5cf3a4ae8c62d929d0f5719b/solution_5cf3d0878c62d929d0f57579.png?version=1)
since, ( mathbf{F} ) is along ( mathbf{r} ) or in radial direction....(Read complete answer below..)