Time taken by the projectile projec...
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Time taken by the projectile projected from P with a velocity v to reach ist. Then length PO equals (A) tv cos 0 (B) tv sin 0 (C) tv sec 0 (D) tv tano

JEE/Engineering Exams
Physics
Solution
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( t_{f}=t quad j^{j} ) ¿ ( =frac{1}{2} cdot g sin theta t^{2}, quad t=frac{2 v}{g cos theta} ) ( frac{1}{2} cdot operatorname{gsin} theta cdot frac{z_{V}}{g cos theta} cdot t quad Rightarrow t^{2}=z x-t ) PP: Vtitano
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