Two chords AB and CD of a circle in...
Question
Two chords AB and CD of a circle intersect at E such that AE=2.4cm.,BE=3.2cm and CE=1.6cm. The length of DE is
Fullscreen

Two chords ( A B ) and ( C D ) of a circle intersect at ( E ) such that ( A E=2.4 mathrm{cm} ., mathrm{BE}=3.2 mathrm{cm} ) and ( mathrm{CE}=1.6 mathrm{cm} . ) The length of ( mathrm{DE} )
is
(a) ( 1.6 mathrm{cm} )
(b) ( 3.2 mathrm{cm} )
(c) ( 4.8 mathrm{cm} )
(d) ( 6.4 mathrm{cm} )

MBA Exams
Maths
Solution
163
Rating
4.0 (1 ratings)
Two chords AB and CD of a circle intersect at E such that AE=2.4cm.,BE=3.2cm and CE=1.6cm. The length of DE is
Fullscreen

(c) Apply the rule, ( A E times E B=C E times E D ) ( Rightarrow quad 2.4 times 3.2=1.6 times mathrm{ED} )
( therefore quad E D=4.8 mathrm{cm} )

Quick and Stepwise Solutions Just click and Send Download App OVER 20 LAKH QUESTIONS ANSWERED Download App for Free