Two particles are released from the same height at an interval of ( 1 mathrm{s} ). How long after the first particle begins to fall will the two particles be ( 10 mathrm{m} ) apart? ( left(g=10 mathrm{ms}^{-2}right) )
(a) ( 1.5 mathrm{s} )
(b) ( 2 mathrm{s} )
(c) ( 1.25 mathrm{s} )
(d) ( 2.5 mathrm{s} )

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( S_{1}=0+frac{1}{2} g(t)^{2} )
( S_{2}=0+frac{1}{2} g(t-1)^{2} )
( ( S_{2}=5 t^{2}+5-10 t )
And ( quad S_{1}-S_{2}=10 )
( 5 t^{2}-left(5 t^{2}-10 t+5right)=10 )
10t - 5 = 10
t = 1.5 sec

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