Question

Dat No of males in oiditg of NHz
[
=frac{0.017}{17}=0
]
mole of ( N H_{3}=6.023 times 10^{23} )
0.001 moles of
( N H_{3}=6.023 times 10^{20} mathrm{mdecule} )
molecule of ( N H_{3}=10 ) pratons ( left(6.023 times 10^{20}right) ) molecule ( =10 times 6.023 times 10^{20} )
( 010430023 times 10^{21} )

# U D. Find out the no of protoners in sing of

Solution