U - J, St + (n - 1 y 2 Solve for x ...
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U - J, St + (n - 1 y 2 Solve for x and y by cross multiplication method : (CBSE = a - b; ax + by = 0? + (CBSE

JEE/Engineering Exams
Maths
Solution
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( a^{3}+b y=a^{3}+b^{3} ) ( Rightarrow quad y=b^{2} ) ( therefore n=a^{2}, y=b^{2} )
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