Question

U - J, St + (n - 1 y 2 Solve for x and y by cross multiplication method : (CBSE = a - b; ax + by = 0? + (CBSE

JEE/Engineering Exams

Maths

Solution

4.0 (1 ratings)

( a^{3}+b y=a^{3}+b^{3} ) ( Rightarrow quad y=b^{2} ) ( therefore n=a^{2}, y=b^{2} )