Question

( 3^{x}=5 x^{y}=(75)^{z}=left(3 x^{5}right)^{z} )
so, ( 3^{x} times 5^{y}=(75)^{2} times(75)^{frac{1}{2}} 3^{2} cdot 5^{2 z} )
So
[
begin{array}{l}
x=3^{22} cdot 5^{4 z}
y=4 z
end{array}
]
[
begin{aligned}
x y &=2 z times 4 z
&=8 z^{2}
2 x+y &=4 z+4 z
&=8 z
50, & frac{x y}{2 x+y}=frac{8 z^{7}}{8 k}=z
end{aligned}
]
Kenel it is proved

# U U xy 25. If 3* = 5y = (75)2, show that z = my 2x + y

Solution