U V 2 1 U1 +U2 ut uz 22 9) A partic...
Question

# U V 2 1 U1 +U2 ut uz 22 9) A particle starts from rest and experiences a constant acceleration for 6 seconds. If it travels a distance d, in the first two seconds, a distance dy in next two seconds

JEE/Engineering Exams
Physics
Solution
122
4.0 (1 ratings)
( u=0 ) constant arceleration for 6 seconds ( s=u t+frac{1}{2} a t^{2} quad d_{1}+alpha_{2}=frac{1}{2} a(4)^{2} ) ( S=frac{1}{2} a times(2)^{2} ) ( S=2 a=d_{1} quad d_{1}+d_{2}=frac{1}{2} a cdot 168 ) [ begin{array}{rl}d_{1}=2 a & d_{1}+d_{2}=8 a d_{2}=6 aend{array} ]