Question

( operatorname { l o g } _ { 0 . 3 } ( x - 1 ) < operatorname { l o g } _ { 0 . 0 9 } ( x - 1 ) longdiv ( 5 - 1 ) = )
[
begin{array}{l}
lg _{0-1}(x-1)(x-1)^{4} 2
(x-1)^{2}>2-1
x^{2}+1-2 x-x+1>0
end{array}
]
( x^{2}+2 )
( x^{2}-3 x+2>0 )
( x^{2}-12-x+23 )
( x(4-2)-1(x-2)>0 )
( (x-1)(x-2)>0 )
begin{tabular}{|lll|l}
hline ( ln s ) & ( (A) ) & ( 2, infty ) &
hline
end{tabular}

# UIO Cxa Tauon 2.1 Q If logoa (x-1) < logas (x-1), then x lies in the interval [IIT 1985) (A) (2, ) (B) (1, 2) (C) (-2, -1) (D) None of these

Solution