Question

( a t m= ) Po can ( mathrm{Ng} )
( P=74: 2 mathrm{cm} mathrm{Hy} )
conuecting ( P=frac{74.2}{76} ) atm ( =0.976 mathrm{atm} )
( Tleft(text { in } K e^{r} ln i nright)=26^{circ} C+273=299 K )
( R=0.0821 ln operatorname{atm} k^{-1} bmod )
Moles of ( N_{2}=frac{operatorname{Man}}{operatorname{Mola} operatorname{man}}=frac{5.25}{28} )
( =0.1875 mathrm{mol} )
( V=frac{n R T}{p} )
( V=frac{0.1875 times 0.0821 times 299}{0.976} )
( v=4 cdot 71 L )

# Ulalily UIC SULULUI 11. Calculate the volume occupied by 5.25 g of nitrogen at 26°C and 74.2 cm of pressure. (4.71 litres) 12. Find the ratio of the number of molecules contained in 1 g of NH. and 1 g of N.

Solution