Question

Let ordinate be ( y )
( & ) abscissa be ( x )
( begin{array}{ll}text { Given } & y=frac{1}{3} x xend{array} )
( [3 y=x] )
putin equ ( quad 3 x+5 y=14 )
( -operatorname{get}_{1} 3(3 y)+5 y=14 )
( 9 y+5 y=14 )
( quad y=17 )
( begin{array}{l}text { & }left[begin{array}{lll}x=3 & text { ) }end{array}right. & text { be }(3,1)end{array} )

# ULUAIJ. Q11 In the graph of the linear equation 3x + 5y = 14, there is a point such that its ordinate is one third of abscissa. Find coordinates of the point. Find the equation of straight line which is parallel to x-axis, and is at a distance of d from x-axis. Shade the trinnale facadh dha aranhaofv =4Y+ =2 and the v-avis Write tha Q12 12

Solution