Question
10. ( c cdot F times L cdot c m= ) Product of Numbers
[
begin{array}{l}12 times 336=84 times x x=frac{12 times 336}{847} x=frac{336}{7} x=48end{array}
]

ULULLLLLL 47. The H.C.F. and L.C.M. of two numbers are 12 and 336 respectively. If one of the numbers is 84, the other is (S.S.C., 2010) TT
Solution
