Question

begin{aligned}( frac{(sec A+1)}{tan A} &=frac{tan A}{sec A-1} {hline(sec A+1)(sec A-1)=tan ^{2} A}{sec ^{2} A-1} &=tan ^{2} A & sec ^{2} A=frac{1+tan ^{2} A}{sec ^{2} A}=sec ^{2} A & 1 cdot 1-1 cdot int cdot=R cdot H cdot int cdot & ) Hence proved end{aligned}

# Uluovo UT COT sec A + 1 tan A tan A sec A - 1

Solution