Question

( -4 quad+1+a^{2}=10^{2} )
2741. ( (0)^{9} x^{4}, 3,2 x^{9}+7 x )
( 7 frac{1}{2}+9^{2}=10^{10083} )
( 2+81=10^{log _{x} 83} )
( Rightarrow quadleft(10^{10}right) 2^{83}=83 )
conen ( x=10 ) in ( 10^{log _{10} 83}=83 )
( x^{2}+tan e quad x=10 )

# UN UC. ou unel PUSiuve real nu 10% If 4A + 9B = 10°, where A = log164, B = log, 9 & C = log,83, then find x.

Solution