Question

Let the Principal was ( P )
for first year, ( R=10 % )
Interest ( =mathrm{PTR} / 10 mathrm{O}=mathrm{P} times 1 times 10 / 100=0.1 mathrm{P} )
Amount at the end of 1 st year ( =P+0.1 P=1.1 mathrm{P} )
For 2 nd year, Principal = 1.1P
( R=12 % )
Interest ( =mathrm{PTR} / 100=1.1 mathrm{P} times 1 times 12 / 100=0.132 mathrm{P} )
Amount at the end of 2 nd year ( =1.1 P+0.132 P=1.232 P )
It is given that amount is 9856
( Rightarrow 1.232 P=9856 )
( Rightarrow P=9856 / 1.232 )
( Rightarrow P=R s .8000 )
Principal was Rs. 8000

# Uompoun Meresi. nat Principal will amount to 9768 in two years, the rates of interest for the successive years are 10% p.a. and 11% p.a. respectively.

Solution