vurul m IIIJ SULUHU UI 115 HIULUI 1...
Question
Fullscreen

vurul m IIIJ SULUHU UI 115 HIULUI 10. A body moving with uniform acceleration covers 12 m in the 2nd second and 20 m in the 4th second of its motion. How much distance will it cover in 4 seconds after the 5th second? UBAT

JEE/Engineering Exams
Physics
Solution
59
Rating
4.0 (1 ratings)
Fullscreen
[ begin{array}{l} B_{t}=u+a frac{(alpha t-1)}{2} 12=u+frac{3 a}{2}, quad text { pad } lambda 2 u+3 a=24 rightarrow 0 20=u+frac{7}{2} a quad Rightarrow quad 2 u+7 a=40 quad rightarrow(2) end{array} ] From ( Q ) and [ left.a=4 mathrm{m} / mathrm{s}^{2}right} quad | u=6 mathrm{m} / mathrm{s} ] Distance in dis abfa sta second, in a s seconds [ begin{array}{l} =left[(6 times 9)+frac{1}{2} 4(9)^{2}right]-left[(6 times 5)+frac{1}{2} 4(5) 2right] =136 mathrm{M} end{array} ]
Quick and Stepwise Solutions Just click and Send Download App OVER 20 LAKH QUESTIONS ANSWERED Download App for Free