Question
Sol: It is clear from the graph that ( y=|sin | x|| ) continuous everywhere but not differentiable
[
x=ldots . .-2 pi,-pi, 0, pi, 2 pi, ldots ldots
]
i.e., ( x=n pi, n in I )
We observe that at all integral values of ( pi, ) fhan sharp corner

W.E-4:Examine the continuity and differentiability of y = sin(x | at x=nn,nel
Solution
