Question

Bohr radius is given as, ( mathrm{r}_{mathrm{n}}=0.529 mathrm{n}^{2} times 10^{-10} mathrm{m} )
given that, diameter ( =20 mathrm{nm} ) Therefore, radius ( =10 mathrm{nm}=10 times 10^{-9} mathrm{m} )
Using Bohr radius equation:
( n^{2}=frac{10 times 10^{-9}}{0.529 times 10^{-10}}=189.03 )
( n=13.74 approx 14 )

# What is likely to be orbit number for a circular orbit of diameter 20 nm of the hydrogen atom : (A) 10 (B) 14 (C) 12 (D) 16

Solution