Question

Nomality ( =frac{1}{100} ) Molewhac man ( =126 mathrm{g} )
Volume ( =250 mathrm{ml}=0.25 mathrm{L} )
n
is
- fallor of oxalin alid ( left(mathrm{h}_{2} mathrm{C}_{2} mathrm{O}_{4}right) )
2 as it can gine ( 2 mathrm{N}^{+} ) ions
Now, equivalent wherght of ( mathrm{H}_{2} mathrm{C}_{2} mathrm{O}_{4} )
= Molulas mass
n fator ( begin{aligned} &=frac{126}{2}=63 mathrm{g} text { Nomatuty } &=left[begin{array}{lll}text { wit. of solute } {[mathrm{q}-mathrm{w} t}end{array}right.& text { Volume in litses } end{aligned} )
Substituting the values, ( frac{1}{100}=frac{text { Wh. of solute }}{63} )
2
( begin{aligned} text { Wh of solute } &=frac{1}{100} times 0.25 times 63 &=0.156 mathrm{g} text { ons }=& text { option }(b) end{aligned} )

# What mass of H,C,02 2H2O (mol. mass = 126) should be dissolved in water to prepare 250 mL of centinormal solution which act as a reducing agent ? (a) 0.63 g (b) 0.1575 g (C) 0.126 g (d) 0.875 g

Solution