Question

ol. ( t=frac{1}{x-1} ) is discontinuous at ( x=1 . ) Also
( y=frac{1}{t^{2}+t-2} ) is discountinuous at ( t=-2 ) and ( t=1 )
When ( t=-2, frac{1}{x-1}=-2 Rightarrow x=frac{1}{2} )
When ( t=1, frac{1}{x-1}=1 Rightarrow x=2 )
So, ( y=f(x) ) is discontinuous at three points, ( x=1, frac{1}{2}, 2 )

# where t=— then x-1 W.E-5: If y = 2+1-2 where fV1 where to the the number of points of discontinuous of y = f(x)xe Ris

Solution