Question

whose hallgers are equal w US IJJ. Prove that 37. sin (270° + A) = -cos A, and tan (270° + A) = -cot A 2000 9200 A A det 1100 A .

JEE/Engineering Exams

Maths

Solution

4.0 (1 ratings)

Can be proved with the help of 4 mit circle eis? ( begin{array}{ll}90^{circ} & text { sim }(270+A)=-cos A text { sio } 7 & text { (As value of sin is ve in } 4^{text {th }}end{array} )