Question

( f=F(x)=3 x^{2}+1 )
( Rightarrow y=3 x^{2}+1 )
( Rightarrow y-1=3 x^{2} )
( Rightarrow x^{2}=frac{8-1}{3} )
( Rightarrow x=sqrt{frac{y-1}{3}}=f^{-1}(x)=sqrt{frac{y-1}{3}} )
Replaing at ( y=x ) we get invere
of ( f(x) d )
je ( f^{-1}(x)=sqrt{frac{x-1}{3}}, e )

# WICIC U, V, art CUISLUI3) A funciton f:R → Ris defined as f(x) = 3x2 +1. Then f-1(x) is : (a) VX-1 (c) f-1 does not exist 3

Solution