Question

( int frac{sin ^{-1} x}{x^{2}} d x+40^{frac{1}{6 / 2}} d x= )
( frac{-sin ^{-1} x-int frac{1}{x} int frac{1}{sqrt{1-x^{2}}left(frac{-1}{x}right)} d x}{frac{sin ^{2} x}{x}+int frac{1}{x sqrt{1-x^{2}}} d x}{frac{sin ^{2} x}{x}+sec ^{-1}(x)+c} )

# x 38./sin*dx [CBSE ’04]

Solution