Question

Phion ( frac{x+1}{x+11} geq 0 )
( frac{1}{-11} leq frac{1+1}{1+x} )
( therefore x in(-infty,-11] cup[-1 infty]] )

# xt >0 then re r+11 (a) (-11, -1) (b) (-11, -1) (6) (-0, -1) U[-1.6) (d) (-11,-1]

Solution

Instasolv

Solution