xt >0 then re r+11 (a) (-11, -1) (b...
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xt >0 then re r+11 (a) (-11, -1) (b) (-11, -1) (6) (-0, -1) U[-1.6) (d) (-11,-1]

JEE/Engineering Exams
Maths
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Phion ( frac{x+1}{x+11} geq 0 ) ( frac{1}{-11} leq frac{1+1}{1+x} ) ( therefore x in(-infty,-11] cup[-1 infty]] )
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