Question
( y=sqrt{x}+frac{1}{sqrt{x}} )
( frac{d y}{d x}=frac{1}{2 sqrt{x}}+left(-frac{1}{2 x sqrt{x}}right) )
( frac{d y}{d x}=frac{1}{2 sqrt{x}}-frac{1}{2 x sqrt{x}} )
( frac{d y}{d x}=frac{x-1}{2 x sqrt{2}} )
mentiply this by ( 2 x )
( 2 x frac{d y}{d x}=frac{x-1}{sqrt{x}} )
( Rightarrow A T G, frac{x-1}{sqrt{x}+sqrt{x}+frac{1}{sqrt{7}}}= )
( A T Q_{1} Rightarrow frac{x-1+x+1}{sqrt{x}} Rightarrow frac{2 x}{sqrt{x}} Rightarrow 2 sqrt{x} )

y se ta Perove that an de +y = 203 va
Solution
